Sequences  Finding The Rule
To find a missing number in a Sequence, first you must know The Rule
Quick Definition of Sequence
Read Sequences and Series for a more indepth discussion, but put simply:
A Sequence is a set of things (usually numbers) that are in order.
Each number in the sequence is called a term (or sometimes "element" or "member"):
Finding Missing Numbers
To find a missing number you need to first find The Rule behind the Sequence.
Sometimes it is just a matter of looking at the numbers and seeing the pattern.
Example: 1, 4, 9, 16, ?
Answer: they are Squares (1^{2}=1, 2^{2}=4, 3^{2}=9, 4^{2}=16, ...)
Rule: x_{n} = n^{2}
Sequence: 1, 4, 9, 16, 25, 36, 49, ...
Did you see how we wrote down the rule with "x" and "n" ?
x_{n} means "term number n", so term 3 would be written x_{3}
And we also used "n" in the formula, so the formula for term 3 is 3^{2} = 9. This could be written
x_{3} = 3^{2} = 9
Once we have The Rule we can use it find any term, for example, the 25th term can be found by "plugging in" 25 wherever n is.
x_{25} = 25^{2} = 625
How about another example:
Example: 3, 5, 8, 13, 21, ?
They are the sum of the two numbers before, that is 3 + 5 = 8, 5 + 8 = 13 and so on (it is actually part of the Fibonacci Sequence):
Rule: x_{n} = x_{n1} + x_{n2}
Sequence: 3, 5, 8, 13, 21, 34, 55, 89, ...
Now what does x_{n1} mean? Well that just means "the previous term" because the term number (n) is 1 less (n1).
So, if n was 6, then x_{n} = x_{6} (the 6th term) and x_{n1} = x_{61} = x_{5} (the 5th term)
So, let's apply the Rule to the 6th term:
x_{6} = x_{61} + x_{62}
x_{6} = x_{5} + x_{4}
We already know the 4th term is 13, and the 5th is 21, so the answer is:
x_{6} = 21_{} + 13 = 34
Pretty simple ... just put numbers instead of "n"
Many Rules
One of the troubles with finding "the next number" in a sequence is that mathematics is so powerful you can often find more then one Rule that works.
What is the next number in the sequence 1, 2, 4, 7, ?
There are (at least) three solutions:
Solution 1: Add 1, then add 2, 3, 4, ...
So, 1+1=2, 2+2=4, 4+3=7, 7+4=11, etc...
Rule: x_{n} = n(n1)/2 + 1
Sequence: 1, 2, 4, 7, 11, 16, 22, ...
(The rule looks a bit complicated, but it works)
Solution 2: Add the two previous numbers, plus 1:
Rule: x_{n} = x_{n1} + x_{n2} + 1
Sequence: 1, 2, 4, 7, 12, 20, 33, ...
Solution 3: Add the three previous numbers
Rule: x_{n} = x_{n1} + x_{n2} + x_{n3}
Sequence: 1, 2, 4, 7, 13, 24, 44, ...
So, we had three perfectly reasonable solutions, and they created totally different sequences.
Which is right? They are all right.

And there will be other solutions.
Hey, it may be a list of the winner's numbers ... so the next number could be ... anything! 
Simplest Rule
When in doubt choose the simplest rule that makes sense, but also mention that there are other solutions.
Finding Differences
Sometimes it helps to find the differences between each number ... this can often reveal an underlying pattern.
Here is a simple case:
The differences are always 2, so we can guess that "2n" is part of the answer.
Let us try 2n:
n: 
1 
2 
3 
4 
5 
Terms (x_{n}): 
7 
9 
11 
13 
15 
2n: 
2 
4 
6 
8 
10 
Wrong by: 
5 
5 
5 
5 
5 
The last row shows that we are always wrong by 5, so just add 5 and we are done:
Rule: x_{n} = 2n + 5
OK, you could have worked out "2n+5" by just playing around with the numbers a bit, but we want a systematic way to do it, for when the sequences get more complicated.
Second Differences
In the sequence {1, 2, 4, 7, 11, 16, 22, ...} we need to find the differences ...
... and then find the differences of those (called second differences), like this:
The second differences in this case are 1.
With second differences you multiply by "n^{2} / 2".
In our case the difference is 1, so let us try n^{2} / 2:
n: 
1 
2 
3 
4 
5 
Terms (x_{n}): 
1 
2 
4 
7 
11 






n^{2}: 
1 
4 
9 
16 
25 
n^{2} / 2: 
0.5 
2 
4.5 
8 
12.5 
Wrong by: 
0.5 
0 
0.5 
1 
1.5 
We are close, but seem to be drifting by 0.5, so let us try: n^{2} / 2  n/2
n^{2} / 2  n/2: 
0 
1 
3 
6 
10 
Wrong by: 
1 
1 
1 
1 
1 
Wrong by 1 now, so let us add 1:
n^{2} / 2  n/2 + 1: 
1 
2 
4 
7 
11 
Wrong by: 
0 
0 
0 
0 
0 
The formula n^{2} / 2  n/2 + 1 can be simplified to n(n1)/2 + 1
So, by "trialanderror" we were able to discover the rule.
Sequence: 1, 2, 4, 7, 11, 16, 22, 29, 37, ...
Other Types of Sequences
As well as the sequences mentioned on Sequences and Series:
 Arithmetic Sequences
 Geometric Sequences
 Fibonacci Sequence
 Triangular, etc Sequences
Look out for
In truth there are too many types of sequences to mention here, but if there is one you would like me to mention just let me know.
